A) \[50{}^\circ \]
B) \[60{}^\circ \]
C) \[80{}^\circ \]
D) \[70{}^\circ \]
Correct Answer: C
Solution :
In\[\Delta PQR,\]\[\angle P+\angle Q+\angle R=180{}^\circ \] \[\angle P=180{}^\circ -\left( 65{}^\circ +35{}^\circ \right)=180{}^\circ -100{}^\circ \] \[\angle P=80{}^\circ \] \[\Delta PQR\cong \Delta UVW,\]\[QR=7.5\,cm\] In \[\Delta UVW,\]\[QR=7.5\,cm\] In \[\Delta UVW,\] angle opposite to 7.5 is \[80{}^\circ \] Hence, \[x=80{}^\circ \]
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