A) 80 N
B) 40 N
C) 20 N
D) 8N
Correct Answer: A
Solution :
Let the weight of the object at earth is\[W\], and at mars be\[{{W}_{m}}\], then \[\frac{{{W}_{m}}}{{{W}_{e}}}=\frac{{{g}_{m}}}{{{g}_{e}}}=\frac{\frac{G{{M}_{m}}}{{{R}_{m}}^{2}}}{{{R}_{e}}^{2}}=\frac{{{M}_{m}}}{{{M}_{e}}}\cdot {{\left( \frac{{{R}_{e}}}{{{R}_{m}}} \right)}^{2}}\] \[=\frac{1}{10}\times {{\left( \frac{6400}{3200} \right)}^{2}}=\frac{4}{10}\] \[\Rightarrow \] \[{{W}_{m}}=\frac{4}{10}We=\frac{4}{10}\times 200=80\,\,N\].
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