A) Fluorine
B) Iodine
C) Chlorine
D) Bromine
Correct Answer: B
Solution :
Reducing properties increase from F to I so it oxidise by nitric acid. \[{{I}_{2}}+10HN{{O}_{3}}\to 2HI{{O}_{3}}+10N{{O}_{2}}+4{{H}_{2}}O\]
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