question_answer

A man whose eye level is 1.5 metres above the ground observes the angle of elevation of a tower to be\[{{60}^{o}}\]. If the distance of the man from the tower be 10 meters, the height of the tower is

A) \[(1.5+10\sqrt{3})\,m\]

B) \[10\,\sqrt{3}\,m\]

C) \[\left( 1.5+\frac{10}{\sqrt{3}} \right)\,m\]

D) None of these

Correct Answer: A

Solution :

\[H=(10\tan {{60}^{o}}+1.5)=(10\sqrt{3}+1.5)m\]