A) 20
B) 23
C) 25
D) 28
Correct Answer: B
Solution :
\[\text{7}\left( \text{7}-\text{1} \right)=\text{42}\to \text{42}+\text{3}=\text{45}\] \[\text{2}\left( \text{2}-\text{1} \right)=\text{2}\to \text{2}+\text{3}=\text{5}\] \[\text{6 }\left( \text{6}-\text{1} \right)=\text{3}0\to \text{3}0+\text{3}=\text{33}\] \[\text{4 }\left( \text{4}-\text{1} \right)=\text{12}\to \text{12}+\text{3}=\text{15}\] \[\text{3 }\left( \text{3}-\text{1} \right)=\text{6}\to \text{6}+\text{3}=\text{9}\] \[\therefore ?=\text{5 }\left( \text{5}-\text{1} \right)=\text{2}0\to \text{2}0+\text{3}=\text{23}\]
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