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JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Integral power of iota, Algebraic operations and Equality of complex numbers

  • question_answer
    \[{{(1+i)}^{10}}\], where \[{{i}^{2}}=-1,\] is equal to [AMU 2001]

    A) 32 i

    B) 64 + i

    C) 24 i - 32

    D) None of these

    Correct Answer: A

    Solution :

    \[{{(1+i)}^{10}}={{[{{(1+i)}^{2}}]}^{5}}={{(2i)}^{5}}=32\,i\].


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