A) 1
B) 2
C) 3
D) 4
Correct Answer: B
Solution :
We have \[{{(1+i)}^{2n}}={{(1-i)}^{2n}}\] \[\Rightarrow {{\left( \frac{1+i}{1-i} \right)}^{2n}}=1\]\[\Rightarrow {{(i)}^{2n}}=1\]\[\Rightarrow {{(i)}^{2n}}={{(-1)}^{2}}\] \[\Rightarrow {{(i)}^{2n}}={{({{i}^{2}})}^{2}}\]\[\Rightarrow {{(i)}^{2n}}={{(i)}^{4}}\]\[\Rightarrow 2n=4\]\[\Rightarrow n=2\].
You need to login to perform this action.
You will be redirected in
3 sec
