A) \[\frac{1}{5}\]
B) \[\frac{3}{5}\]
C) \[\frac{4}{5}\]
D) None of these
Correct Answer: C
Solution :
We have\[\frac{{{(1+i)}^{2}}}{2-i}=\frac{(2i)(2+i)}{(2-i)(2+i)}\]\[=-\frac{2}{5}+i\frac{4}{5}\]. Thus Im \[(z)=\frac{4}{5}\].
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