question_answer

If \[\text{cos3x}=\text{cos 3}0{}^\circ \text{ sin 6}0{}^\circ \text{ }-\] \[\text{sin 3}0{}^\circ \text{ cos 6}0{}^\circ \] , find the value of x.

A)  \[\text{6}0{}^\circ \]                     

B)  \[\text{45}{}^\circ \] 

C)  \[\text{2}0{}^\circ \]     

D)         \[\text{3}0{}^\circ \]