A) \[\text{9}0{}^\circ \]
B) \[\text{45}{}^\circ \]
C) \[\text{3}0{}^\circ \]
D) \[\text{6}0{}^\circ \]
Correct Answer: D
Solution :
\[\text{6}0={{\text{2}}^{\text{2}}}\times \text{3}\times \text{5}\] \[\therefore \]\[={{2}^{2}}\times 3\times 5\times 2=120\] \[f(p)={{\text{p}}^{\text{3}}}+\text{6}{{\text{p}}^{\text{2}}}+\text{lip}+\text{6}\] [Applying Componendo- Dividendo on both sides] \[f(p)\]\[p(x)={{x}^{2}}+3x-2\]\[\Rightarrow \] \[p(-1)={{(-1)}^{2}}+3(-1)-2=(-4)\] \[p(-1)=-4\]\[({{m}^{2}}+9){{x}^{2}}+13x+6m\]\[({{m}^{2}}+9){{x}^{2}}+13x+6m\] \['x'\]
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