A) \[\frac{-2\pi }{3}\]
B) \[\frac{-\pi }{3}\]
C) \[\frac{-2\pi }{3}\]
D) \[\frac{5\pi }{3}\]
Correct Answer: B
Solution :
\[{{\sin }^{-1}}\,\left( \frac{-\sqrt{3}}{2} \right)=-{{\sin }^{-1}}\left( \frac{\sqrt{3}}{2} \right)=-\frac{\pi }{3}\].
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