JEE Main & Advanced Mathematics Inverse Trigonometric Functions Question Bank Inverse trigonometric functions

  • question_answer
    The principal value of \[{{\sin }^{-1}}\left( \sin \frac{5\pi }{3} \right)\]is [MP PET 1996]

    A) \[\frac{5\pi }{3}\]

    B) \[-\frac{5\pi }{3}\]

    C) \[-\frac{\pi }{3}\]

    D) \[\frac{4\pi }{3}\]

    Correct Answer: C

    Solution :

      \[{{\sin }^{-1}}\,\left( \sin \frac{5\pi }{3} \right)={{\sin }^{-1}}\,\left( -\frac{\sqrt{3}}{2} \right)=-\frac{\pi }{3}\].


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