JEE Main & Advanced Mathematics Inverse Trigonometric Functions Question Bank Inverse trigonometric functions

  • question_answer
    The value of \[\cos ({{\tan }^{-1}}(\tan 2))\]is [AMU 2002]

    A) \[\frac{1}{\sqrt{5}}\]

    B) \[-\frac{1}{\sqrt{5}}\]

    C) \[\cos \,2\]

    D) \[-\cos 2\]

    Correct Answer: C

    Solution :

      \[\cos [{{\tan }^{-1}}(\tan 2)]=\cos 2\].


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