JEE Main & Advanced Mathematics Inverse Trigonometric Functions Question Bank Inverse trigonometric functions

  • question_answer
    \[{{\tan }^{-1}}1+{{\tan }^{-1}}2+{{\tan }^{-1}}3=\]

    A) \[\frac{\pi }{2}\]

    B) \[\frac{\pi }{4}\]

    C) 0

    D) None of these

    Correct Answer: D

    Solution :

      \[{{\tan }^{-1}}1+{{\tan }^{-1}}2+{{\tan }^{-1}}3\] \[={{\tan }^{-1}}1+\pi +{{\tan }^{-1}}\left( \frac{5}{-5} \right)\]\[={{\tan }^{-1}}1+\pi -{{\tan }^{-1}}1=\pi \].


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