JEE Main & Advanced Mathematics Inverse Trigonometric Functions Question Bank Inverse trigonometric functions

  • question_answer
    \[{{\cos }^{-1}}\sqrt{1-x}+{{\sin }^{-1}}\sqrt{1-x}=\]

    A) \[\pi \]

    B) \[\frac{\pi }{2}\]

    C) 1

    D) 0

    Correct Answer: B

    Solution :

     \[{{\cos }^{-1}}\sqrt{1-x}+{{\sin }^{-1}}\sqrt{1-x}={{\sin }^{-1}}\sqrt{x}+{{\cos }^{-1}}\sqrt{x}=\frac{\pi }{2}\].


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