JEE Main & Advanced Mathematics Inverse Trigonometric Functions Question Bank Inverse trigonometric functions

  • question_answer
    \[2{{\sin }^{-1}}\frac{3}{5}+{{\cos }^{-1}}\frac{24}{25}=\]

    A) \[\frac{\pi }{2}\]

    B) \[\frac{2\pi }{3}\]

    C) \[\frac{5\pi }{3}\]

    D) None of these

    Correct Answer: A

    Solution :

      \[2\,{{\sin }^{-1}}\frac{3}{5}+{{\cos }^{-1}}\frac{24}{25}={{\sin }^{-1}}2\times \frac{3}{5}\sqrt{1-\frac{9}{25}}+{{\cos }^{-1}}\frac{24}{25}\] \[={{\sin }^{-1}}\frac{24}{25}+{{\cos }^{-1}}\frac{24}{25}=\frac{\pi }{2}\].


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