A) \[\frac{\pi }{3}\]
B) \[\frac{\pi }{4}\]
C) \[\frac{\pi }{6}\]
D) \[\frac{\pi }{2}\]
Correct Answer: B
Solution :
\[{{\cot }^{-1}}3+\text{cose}{{\text{c}}^{-1}}\sqrt{5}={{\cot }^{-1}}3+{{\cot }^{-1}}2\] \[={{\cot }^{-1}}\left( \frac{3\times 2-1}{3+2} \right)={{\cot }^{-1}}(1)=\frac{\pi }{4}\].
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