A) 4
B) 5
C) 1
D) 3
Correct Answer: D
Solution :
\[{{\sin }^{-1}}\frac{x}{5}+\text{cose}{{\text{c}}^{-1}}\frac{5}{4}=\frac{\pi }{2}\Rightarrow {{\sin }^{-1}}\frac{x}{5}=\frac{\pi }{2}-\text{cose}{{\text{c}}^{-1}}\frac{5}{4}\] Þ \[{{\sin }^{-1}}\frac{x}{5}=\frac{\pi }{2}-{{\sin }^{-1}}\frac{4}{5}\]Þ \[{{\sin }^{-1}}\frac{x}{5}={{\cos }^{-1}}\frac{4}{5}\] Þ \[{{\sin }^{-1}}\left( \frac{x}{5} \right)={{\sin }^{-1}}\frac{3}{5}\]Þ \[x=3\].
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