JEE Main & Advanced Mathematics Inverse Trigonometric Functions Question Bank Inverse trigonometric functions

  • question_answer
    \[\sin \left\{ {{\sin }^{-1}}\frac{1}{2}+{{\cos }^{-1}}\frac{1}{2} \right\}=\]  [EAMCET 1985]

    A) 0

    B) -1

    C) 2

    D) 1

    Correct Answer: D

    Solution :

    \[\sin \left( {{\sin }^{-1}}\frac{1}{2}+{{\cos }^{-1}}\frac{1}{2} \right)=\sin \frac{\pi }{2}=1\].


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