JEE Main & Advanced Mathematics Inverse Trigonometric Functions Question Bank Inverse trigonometric functions

  • question_answer
    \[{{\sin }^{-1}}\frac{4}{5}+2{{\tan }^{-1}}\frac{1}{3}=\]  [ISM Dhanbad 1971]

    A) \[\frac{\pi }{2}\]

    B) \[\frac{\pi }{3}\]

    C) \[\frac{\pi }{4}\]

    D) None of these

    Correct Answer: A

    Solution :

    \[{{\sin }^{-1}}\frac{4}{5}={{\tan }^{-1}}\frac{4}{3},\text{ }2{{\tan }^{-1}}\frac{1}{3}={{\tan }^{-1}}\frac{3}{4}={{\cot }^{-1}}\frac{4}{3}\]and \[{{\tan }^{-1}}x+{{\cot }^{-1}}x=\frac{\pi }{2}\].


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