JEE Main & Advanced Mathematics Inverse Trigonometric Functions Question Bank Inverse trigonometric functions

  • question_answer
    If \[{{\tan }^{-1}}x+2{{\cot }^{-1}}x=\frac{2\pi }{3},\]then x = [Karnataka CET 1999]

    A) \[\sqrt{2}\]

    B) 3

    C) \[\sqrt{3}\]

    D) \[\frac{\sqrt{3}-1}{\sqrt{3}+1}\]

    Correct Answer: C

    Solution :

     The given equation may be written as \[{{\tan }^{-1}}x+{{\cot }^{-1}}x+{{\cot }^{-1}}x=\frac{2\pi }{3}\] Þ \[{{\cot }^{-1}}x=\frac{2\pi }{3}-\frac{\pi }{2}\] = \[\frac{\pi }{6}\] Þ \[x=\sqrt{3}\].


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