JEE Main & Advanced Mathematics Inverse Trigonometric Functions Question Bank Inverse trigonometric functions

  • question_answer
    If \[{{\sin }^{-1}}\frac{3}{5}+{{\cos }^{-1}}\left( \frac{12}{13} \right)={{\sin }^{-1}}C,\]then C = [Pb. CET 1999]

    A) \[\frac{65}{56}\]

    B) \[\frac{24}{65}\]

    C) \[\frac{16}{65}\]

    D) \[\frac{56}{65}\]

    Correct Answer: D

    Solution :

      Given \[{{\sin }^{-1}}C={{\sin }^{-1}}\frac{3}{5}+{{\cos }^{-1}}\frac{12}{13}\]  \[\Rightarrow C=\sin \left( {{\sin }^{-1}}\frac{3}{5}+{{\cos }^{-1}}\frac{12}{13} \right)\] using, \[\sin (A+B)=\sin A\,\,\cos B+\cos A\,\sin B\] \[\Rightarrow \,\,C=\frac{3}{5}\times \frac{12}{13}+\sqrt{1-\frac{9}{25}}\sqrt{1-\frac{144}{169}}\]\[\Rightarrow C=\frac{56}{65}\].


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