JEE Main & Advanced Mathematics Inverse Trigonometric Functions Question Bank Inverse trigonometric functions

  • question_answer
    The value of \[{{\sin }^{-1}}\left( \frac{\sqrt{3}}{2} \right)-{{\sin }^{-1}}\left( \frac{1}{2} \right)\]is [MP PET 2003]

    A) \[{{45}^{o}}\]

    B) \[{{90}^{o}}\]

    C) \[{{15}^{o}}\]

    D) \[{{30}^{o}}\]

    Correct Answer: D

    Solution :

      \[{{\sin }^{-1}}\left[ \frac{\sqrt{3}}{2} \right]-{{\sin }^{-1}}\left[ \frac{1}{2} \right]={{60}^{o}}-{{30}^{o}}={{30}^{o}}\].


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