A) \[x+y+xy=1\]
B) \[x+y-xy=1\]
C) \[x+y+xy+1=0\]
D) \[x+y-xy+1=0\]
Correct Answer: B
Solution :
\[{{\tan }^{-1}}x+{{\tan }^{-1}}y=\frac{\pi }{4}\]; \[{{\tan }^{-1}}\left( \frac{x+y}{1-xy} \right)={{\tan }^{-1}}1\] \[\frac{x+y}{1-xy}=1\]; \[x+y+xy=1\].
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