JEE Main & Advanced Mathematics Inverse Trigonometric Functions Question Bank Inverse trigonometric functions

  • question_answer
    \[\sin \text{ }\left[ 3\,{{\sin }^{-1}}\left( \frac{1}{5} \right) \right]=\]  [Kerala (Engg.) 2005]

    A) 71/125

    B) 74/125

    C) 3/5

    D) 1/2     

    E)   - 3/5

    Correct Answer: A

    Solution :

      \[\sin \left[ 3{{\sin }^{-1}}\frac{1}{5} \right]\] \[=\sin \left[ {{\sin }^{-1}}\left\{ 3\text{ }\left( \frac{1}{5} \right)-4\text{ }{{\left( \frac{1}{5} \right)}^{3}} \right\} \right]\] \[=\sin \left[ {{\sin }^{-1}}\left\{ \frac{3}{5}-\frac{4}{125} \right\} \right]\]\[=\sin \left[ {{\sin }^{-1}}\left( \frac{75-4}{125} \right) \right]\] \[=\sin \left[ {{\sin }^{-1}}\frac{71}{125} \right]=\frac{71}{125}\].


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