A) \[Ni{{(CO)}_{4}}\]
B) \[Ni{{(C{{l}_{4}})}^{2-}}\]
C) \[Ni(Br)_{4}^{2-}\]
D) \[NiC{{l}_{2}}.4{{H}_{2}}O\]
Correct Answer: A
Solution :
\[CO\] is a strong ligand so induce pairing of electrons and hence \[Ni{{(CO)}_{4}}\] is diamagnetic.
You need to login to perform this action.
You will be redirected in
3 sec
