question_answer

Write the equation of state for \[\mathbf{16}\text{ }\mathbf{g}\] of\[{{\mathbf{O}}_{\mathbf{2}}}\].

Answer:

                Number of moles in \[32g\] of \[{{O}_{2}}=1\] \[\therefore \]Number of moles in \[\text{16 g}\] of \[{{\text{O}}_{2}}=\frac{1}{32}\times 16=\frac{1}{2}\] As \[\text{PV}=\text{nRT}\] and \[n=1/2,\],so \[PV=\frac{1}{2}RT.\]