11th Class Physics Thermal Properties of Matter / द्रव्य के तापीय गुण Question Bank Kinetic Theory of Gases Conceptual Problems

  • question_answer
    In an experiment, the specific heats of some inert gases (at ordinary temperatures) are measured to be as follows:  
    Gas Atomic mass \[(u)\] Specific heat (cal\[{{\mathbf{g}}^{\mathbf{-1}}}{{\mathbf{K}}^{\mathbf{-1}}}\])
    Helium 4.00 0.748
    Neon 20.18 0.147
    Argon 39.94 0.0760
    Krypton 83.80 0.0358
    Xenon 131.3 0.0226
      Try to discover a regularity in the data and explain it on the basis of kinetic energy.             

    Answer:

                    Molar specific heat \[=\] Atomic mass \[\times \] specific heat
    Gas   Molar specific heat
    Helium \[4.00\times 0.748=2.992\] \[\text{cal mo}{{\text{l}}^{\text{-1}}}{{\text{K}}^{\text{-1}}}\]
    Neon \[20.18\times 0.147=2.966\]\[\text{cal mo}{{\text{l}}^{\text{-1}}}{{\text{K}}^{\text{-1}}}\]
    Argon \[39.94\times 0.0760=3.035\]\[\text{cal mo}{{\text{l}}^{\text{-1}}}{{\text{K}}^{\text{-1}}}\]
    Krypton \[83.80\times 0.0358=3.000\]\[\text{cal mo}{{\text{l}}^{\text{-1}}}{{\text{K}}^{\text{-1}}}\]
    Xenon \[131.3\times 0.0226=2.967\]\[\text{cal mo}{{\text{l}}^{\text{-1}}}{{\text{K}}^{\text{-1}}}\]
     Thus the molar specific heat of each gas is nearly\[\text{3 cal mo}{{\text{l}}^{\text{-1}}}{{\text{K}}^{\text{-1}}}.\] It should be so on the basis of kinetic theory of gases according to which for a monoatomic gas, \[{{C}_{V}}=\frac{3}{2}R=\frac{3}{2}\times 2\,cal\,mo{{l}^{-1}}{{K}^{-1}}\] \[=3\,cal\,mo{{l}^{-1}}\,{{K}^{-1}}.\]


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