A) A > B > C > D > E
B) B > A > D > C > E
C) D > B > C > A > E
D) B > C > D > E > A
Correct Answer: B
Solution :
\[2C<A+E,A+E=C+D\] \[\Rightarrow 2C<C+D\Rightarrow C<D\] .......... (a) \[A+D=B+C,C<D\Rightarrow A<B\] .......... (b) \[2A>B+D,A<B\Rightarrow A>D\] .......... (c) \[A+E=C+D,A>D\Rightarrow E<C\] .......... (d)
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