Answer:
The net acceleration of the elevator accelerating upwards\[=g+a\] \[\therefore \] Pressure inside the elevator \[=h\rho (g+a)=\frac{76\times 13.6\times (g+a)}{13.6\times g}\text{ cm of Hg}\] Clearly, this pressure will be greater than\[\text{76 cm of Hg}\].
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