| The perimeter of square \[\mathbf{X}\] is\[\mathbf{20}\,\,\mathbf{cm}\], and that of square \[\mathbf{Y}\] is\[\mathbf{36}\,\,\mathbf{cm}\]. |
A) \[25\,\,c{{m}^{2}}\]
B) \[106\,\,c{{m}^{2}}\]
C) \[56\,\,c{{m}^{2}}\]
D) \[81\,\,c{{m}^{2}}\]
Correct Answer: B
Solution :
The total area of \[X\] and \[Y\] is \[[(5\times 5)+(9\times 9)]c{{m}^{2}}\] \[=(25+81)c{{m}^{2}}=106\,\,c{{m}^{2}}\]
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