If the breadth of the rectangle is\[5\,\,cm\], what is its area?
A) \[55\,\,c{{m}^{3}}\]
B) \[55\,\,{{m}^{2}}\]
C) \[55\,\,c{{m}^{2}}\]
D) \[55\,\,k{{m}^{2}}\]
Correct Answer: C
Solution :
Area of square\[=64\,\,c{{m}^{2}}\] Side of square\[=8\,\,cm\] Its perimeter \[=4\times 8\,\,cm=32\,\,cm\] Perimeter of rectangle\[=2(5+\ell )\] \[\frac{32}{2}-5=\ell \Rightarrow (16-5)cm=11\,\,cm\] Area\[=\ell \times b\] \[=11\times 5=55\,\,c{{m}^{2}}\]
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