A) 250 sq cm
B) 200 sq cm
C) 300 sq cm
D) 275 sq cm
Correct Answer: D
Solution :
Given, \[AB=5\text{ }cm,\text{ }AC=10\text{ }cm\] From right angled \[\Delta ABC,\] \[B{{C}^{2}}=A{{B}^{2}}+A{{C}^{2}}\] \[={{5}^{2}}+{{10}^{2}}=125\] \[\therefore \] \[BC=\sqrt{125}=5\sqrt{5}\,cm\] Hence, total area of bounded region = Area of sq. AD + Area of sq. Ab +Area of sq. CF + Area of \[\Delta \,ABC\] \[={{(5)}^{2}}+{{(10)}^{2}}+{{(5\sqrt{5})}^{2}}+\frac{1}{2}\times 5\times 10\] \[=25+100+125+25=275\,sq.\,cm.\]
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