A) \[\text{7225 }{{\text{m}}^{\text{2}}}\]
B) \[\text{723}0\text{ }{{\text{m}}^{\text{2}}}\]
C) \[\text{7235 }{{\text{m}}^{\text{2}}}\]
D) \[\text{724}0{{\text{m}}^{\text{2}}}\]
Correct Answer: A
Solution :
Area of field ABGFEA = Area of \[\Delta \,ABC+\] Area of trap. CBGH + Area of \[\Delta \,HGF+\]Area of \[\Delta \,FDE+\]Area of \[\Delta \,ADE\] \[=\frac{1}{2}\times 40\times 35+\frac{1}{2}(35+50)\times 50+\frac{1}{2}\times 50\times 50\] \[+\frac{1}{2}\times 45\times 90+\frac{1}{2}\times 50\times 45\] \[=700+2125+1250+2025+1125=7225{{m}^{2}}\]
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