A) \[\text{2}.0{{\text{m}}^{\text{2}}}\]
B) \[\text{2}.\text{15}{{\text{m}}^{\text{2}}}\]
C) \[\text{2}.\text{16}{{\text{m}}^{\text{2}}}\]
D) \[\text{2}.\text{2}{{\text{m}}^{2}}\]
Correct Answer: C
Solution :
Let the side of single new cube be a. Then \[{{a}^{3}}={{30}^{3}}+{{40}^{3}}+{{50}^{3}}\] \[={{10}^{3}}\,(27+64+125)\] \[={{10}^{3}}\times {{6}^{3}}\] \[\therefore \] \[a=60\,cm\] Total surface area of new cube \[=6{{a}^{2}}=6\times {{60}^{2}}\] \[=21600\,c{{m}^{2}},\] i.e. \[2.16\,{{m}^{2}}\]
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