A) 19
B) 20
C) 30
D) 40
Correct Answer: C
Solution :
Area of the base \[=\frac{1}{2}\times {{(16)}^{2}}\times \frac{\sqrt{3}}{2}\] \[=64\sqrt{3}\,c{{m}^{2}}\] \[\therefore \]Height \[=\frac{Volume}{Area\,of\,the\,base}\] \[=\frac{1920\sqrt{3}}{64\sqrt{3}}=30cm\]
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