A) tripled
B) doubled
C) made half
D) None of these
Correct Answer: B
Solution :
Let the initial length and breadth be \[l\]and b respectively. So, the initial perimeter\[=2\,(l+b)\] The final perimeter\[=2\,(2l+2b)\] \[=4\,(l+b)\] Now, \[\frac{\text{Final}\,\text{perimeter}}{\text{Initial}\,\text{perimeter}}=\frac{4\,(l+b)}{2(l+b)}=2.\]You need to login to perform this action.
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