A) \[225\,c{{m}^{2}}\]
B) \[225\sqrt{3}\,c{{m}^{2}}\]
C) \[5\sqrt{2}\,c{{m}^{2}}\]
D) None of these
Correct Answer: A
Solution :
As shown in the diagram below, in the isosceles right triangle, the base is bisected by the altitude and BD = AD.
\[\therefore AD=15\,cm\] Area\[=\frac{1}{2}\times \]base\[\times \]height \[=\frac{1}{2}\times 30\times 15=225\,c{{m}^{2}}\]
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