7th Class Mathematics Mensuration Question Bank Mensuration

  • question_answer
    In the figure, AD = 4 cm, CE = 6 cm, AE = 5 cm and BE = 3 cm. The area of the quadrilateral ABCD is:

    A)  \[24\,c{{m}^{2}}\]                         

    B)  \[34\,c{{m}^{2}}\]

    C)  \[72\,c{{m}^{2}}\]                         

    D)  \[48\,c{{m}^{2}}\]

    Correct Answer: B

    Solution :

        Area of ABCD = Area of trapezium AECD + Area of\[\Delta \]BCE \[=\left[ \frac{1}{2}\times (4+6)\times 5+\frac{1}{2}\times 3\times 6 \right]\] \[=25+9=34\,c{{m}^{2}}.\]


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