A) \[75\,c{{m}^{2}}\]
B) \[77\,c{{m}^{2}}\]
C) \[\frac{231}{4}\,c{{m}^{2}}\]
D) \[\frac{77}{4}\,c{{m}^{2}}\]
Correct Answer: B
Solution :
Area of region \[(A+C)=\frac{22}{7}\times \frac{1}{2}\times 7\times 7\] \[=77\,c{{m}^{2}}.\] Area of region C = Area of region B \[=\frac{22}{7}\times \frac{1}{2}\times \frac{7}{2}\times \frac{7}{2}\] \[=\frac{77}{4}c{{m}^{2}}\] Area of region A = Area of (A + C) ? Area of C \[=\left( 77-\frac{77}{4} \right)c{{m}^{2}}\] Required area = Area of A + Area of B \[=\left( 77-\frac{77}{4} \right)+\left( \frac{77}{4} \right)c{{m}^{2}}\] \[=77c{{m}^{2}}.\]
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