Answer:
(a) When dilute sulphuric acid is poured on a copper plate, the copper metal reacts with sulphuric acid to liberate hydrogen gas. Copper\[(Cu)+\]Sulphuric acid\[({{H}_{2}}S{{O}_{4}})\]\[\to \] Copper sulphte\[(CuS{{O}_{4}})+\]Hydrogen gas\[({{H}_{2}})\] (b) Iron being more reactive displaces copper from copper sulphate solution. In this reaction, the blue colour of copper sulphate fades and there is deposition of copper on the iron nail. Iron\[(Fe)+\]Copper sulphate\[(CuS{{O}_{4}})\to \]Iron sulphate\[(FeS{{O}_{4}})+\]Copper\[(Cu)\]
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