A) \[S{{O}_{2}}\]
B) \[S{{O}_{3}}\]
C) \[{{H}_{2}}{{S}_{2}}{{O}_{7}}\]
D) \[{{H}_{2}}S{{O}_{4}}\]
Correct Answer: D
Solution :
Nitric acid oxidizes sulphur to \[{{H}_{2}}S{{O}_{4}}\] as shown below. \[S+6HN{{O}_{3}}\to {{H}_{2}}S{{O}_{4}}+6N{{O}_{2}}+2{{H}_{2}}O\]
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