A) 8 coins of 25p, 6 coins of 50p & 6 coins of Re 1.
B) 2 coins of 25p, 12 coins of 50p & 4 coins of Re 1.
C) 8 coins of 25p. 4 coins of 50p & 5 coins of Re 1.
D) 4 coins of 25p, 8 coins of 50p & 5 coins of Re 1.
Correct Answer: D
Solution :
Let's check all option one by one: In option, 8 coins of 25p, 6 coins of 50p & 6 coins of Re 1 Total amount = 8\[\times \]Rs.0.25 + 6\[\times \]Rs.0.50 + 6\[\times \]Re 1 = Rs.2+ Rs.3 + Rs.6 = Rs.11, it's not a right combination. In option, 2 coins of 25p. 12 coins of 50p & 4 coins of Re 1 Total amount = 2\[\times \]Rs.0.25 +12\[\times \]Rs.0.50 + 4\[\times \]Re 1 = Rs.0.50 + Rs.6 + Rs.4 = Rs.10.50, it's not a right combination In option, 8 coins of 25p, 4 coins of 50p & 5 coins of Re 1 Total amount = 8\[\times \]Rs.0.25 + 4\[\times \]Rs.0.50 + 5\[\times \]Re 1 = Rs.4 + Rs.2 + Rs.5 = Rs.11, it's not a right combination. In option, 4 coins of 25p, 8 coins of 50p & 5 coins of Re 1 Total amount = 4\[\times \]Rs.0.25 + 8\[\times \]Rs.0.50 + 5\[\times \]Re 1 Re1 + Rs.4 + Rs.5 = Rs.10, it?s a right combination. Hence, Raj can buy ice-cream with money in option.
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