When the trolleys are released, the acceleration Of X is \[\text{2 m}/{{\text{s}}^{\text{2}}}\] to the right. What is the initial acceleration of trolley Y to the left?
A) \[\text{1m}/{{\text{s}}^{\text{2}}}\]
B) \[\text{2 m}/{{\text{s}}^{\text{2}}}\]
C) \[\text{3 m}/{{\text{s}}^{\text{2}}}\]
D) \[\text{4 m}/{{\text{s}}^{\text{2}}}\]
Correct Answer: D
Solution :
Trolley X has twice the mass, hence half the acceleration compared to Y. This is also a demonstration of Newton?s third law about and equal and opposite reaction force.
You need to login to perform this action.
You will be redirected in
3 sec
