question_answer

The greatest height to which a man can throw a stone is h. What will be the greatest distance up to which he can throw the stone?

Answer:

                Maximum height attained, \[H=\frac{{{u}^{2}}{{\sin }^{2}}\theta }{2g}\] Clearly, H will be maximum when \[\sin \theta =1\] \[\therefore \]  \[{{H}_{\max }}=\frac{{{u}^{2}}}{2g}=h\] Maximum horizontal range, \[{{R}_{\max }}=\frac{{{u}^{2}}}{g}=2h\].