question_answer

A projectile of mass m is fired with velocity \[\upsilon \] at an angle \[\theta \] with the horizontal. What is the change in momentum as it rises to the highest point of the trajectory?

Answer:

                Horizontal component of velocity remains constant. The vertical component is \[\upsilon \] sin \[\theta \] at the point of projection and zero at the highest point. Magnitude of change in momentum \[=m(\upsilon \sin \theta -0)=m\upsilon \sin \theta \] (in the vertical direction)