question_answer

Is it important in the long jump that how much height you take for jumping? What factors determine the span of a jump?

Answer:

                Yes, for the longest jump the player should throw himself at an angle of \[\text{45}{}^\circ \] with respect to horizontal. The vertical height for this angle is \[H={{u}^{2}}{{\sin }^{2}}{{45}^{\circ }}/2g={{u}^{2}}/4g,\] where \[u\]is the velocity of projection. If the vertical height is different from \[{{u}^{2}}/4g,\] then the angle will be different from \[\text{45}{}^\circ \] and the horizontal distance covered will also be less. Clearly, the span of jump depends upon (i) the initial velocity of the jump, (ii) the angle of projection.