question_answer

A body is thrown horizontally with a velocity \[\upsilon \] from a tower of height H. After how much time and at what distance from the base of the tower will the body strike the ground?

Answer:

                Clearly, \[H=\frac{1}{2}g{{t}^{2}}\] \[\therefore \]  \[t=\sqrt{\frac{2H}{g}}.\] Distance from the base of the tower, \[x=\upsilon t=\upsilon \sqrt{2H/g}.\]