question_answer

If in case of a motion, displacement is directly proportional to the square of the time elapsed, what do you think about its acceleration i.e., constant or variable? Explain why.             

Answer:

                 Given \[x\propto {{t}^{2}}\] or              \[x=c{{t}^{2}},\] where \[c\] is a constant Velocity,     \[\upsilon =\frac{dx}{dt}=c\times 2t\] Acceleration, \[a=\frac{d\upsilon }{dt}=2c=a\] constant Hence the object is moving with uniform acceleration.