A) \[\text{2 m}/{{\text{s}}^{\text{2}}}\]
B) \[~\text{3 m }/{{\text{s}}^{\text{2}}}\]
C) \[\text{4 m}/{{\text{s}}^{\text{2}}}\]
D) \[~\text{6 m}/{{\text{s}}^{\text{2}}}\]
Correct Answer: A
Solution :
Let \[u\] be the initial velocity and \[a\] be the acceleration. Then, \[s=ut+\frac{1}{2}a{{t}^{2}}\] \[\therefore \] \[150=u\times 10+\frac{1}{2}a\times 100\] ? (i) We know\[{{s}_{n}}=u+\frac{a}{2}(2n-1)\] \[24=u+\frac{a}{2}(20-1)\] ... (ii) Solving equations (i) and (ii), we get\[a=\mathbf{2}\,\,\mathbf{m/}{{\mathbf{s}}^{\mathbf{2}}}\]
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